Question

A boat moving at 13 mi/hr is crossing a river in which the current flowing at 6 mi/hr.ln what direction should the boat head if it is to reach a point on other side of the river directly opposite its starting point.

Please help me I really don't know what to do..

Answer 1

X = 6 mi/h = Velocity of the current.
Y = 13 mi/h = Velocity of the boat.

Tan A = Y/X = 13/6 = 2.16666.
A = 65.2o N. of E. = 24.8o E. of N. Due
to the current.

Direction: Head 24.8o W. of N. To offset
affect of the current.




Tan A =