Asked by jae
A boat moving at 13 mi/hr is crossing a river in which the current flowing at 6 mi/hr.ln what direction should the boat head if it is to reach a point on other side of the river directly opposite its starting point.
Please help me I really don't know what to do..
Please help me I really don't know what to do..
Answers
Answered by
Henry
X = 6 mi/h = Velocity of the current.
Y = 13 mi/h = Velocity of the boat.
Tan A = Y/X = 13/6 = 2.16666.
A = 65.2o N. of E. = 24.8o E. of N. Due
to the current.
Direction: Head 24.8o W. of N. To offset
affect of the current.
Tan A =
Y = 13 mi/h = Velocity of the boat.
Tan A = Y/X = 13/6 = 2.16666.
A = 65.2o N. of E. = 24.8o E. of N. Due
to the current.
Direction: Head 24.8o W. of N. To offset
affect of the current.
Tan A =
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