Asked by J
A boat moving at 5 mi/h is to cross a river in which the current is flowing at 3 mi/h. In what direction should the boat head to reach a point on the other bank of the river directly opposite the starting point?
Answers
Answered by
Henry
X = Vc = 3 m/s.
Y = Vb = 5 m/s.
Tan A = Y/X = 5/3 = 1.66667.
A = 59o N. of E. = 31o E. of N.
Direction = 31o W. of N.
Y = Vb = 5 m/s.
Tan A = Y/X = 5/3 = 1.66667.
A = 59o N. of E. = 31o E. of N.
Direction = 31o W. of N.
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