Asked by Sarah
The linearization at a=0 to sqrt(6+6x) is A+Bx where A is:_____ and where B is:_____
Answers
Answered by
Steve
y = √(6+6x)
y(0) = √6
y' = 1/2 * 1/√(6+6x) * 6 = 3/√(6+6x)
y'(0) = 3/√6 = √6/2
so, y = √6/2 x + √6
A = √6
B = √6/2
y(0) = √6
y' = 1/2 * 1/√(6+6x) * 6 = 3/√(6+6x)
y'(0) = 3/√6 = √6/2
so, y = √6/2 x + √6
A = √6
B = √6/2
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