Asked by Anna
What is the linearization of f(x)=e^x at x=1?
Answers
Answered by
MathMate
Linearization is the approximation of the derivative of the function by a tangent line at a particular point.
f(x)=e<sup>x</sup>
f'(x)=e<sup>x</sup>
at x=1, f'(1)=e
So the tangent of slope "e" passes through the point (1,e).
The equation of the tangent line is therefore
(y-e)=e(x-1)
y=e*x-e+e
=e*x
See figure at the link below, and note that the line y=e*x passes through the origin.
http://img607.imageshack.us/img607/4157/1291771397.png
f(x)=e<sup>x</sup>
f'(x)=e<sup>x</sup>
at x=1, f'(1)=e
So the tangent of slope "e" passes through the point (1,e).
The equation of the tangent line is therefore
(y-e)=e(x-1)
y=e*x-e+e
=e*x
See figure at the link below, and note that the line y=e*x passes through the origin.
http://img607.imageshack.us/img607/4157/1291771397.png
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