Asked by Vick
Find the linearization of the function below at x = π/3.?
y=sin(x)/x
Your answer should be a linear function of x where the coefficients are accurate to at least two decimal places. You can enter π in your answer as "pi" (without the quotes).
I am not able to figure out how to find the answer. I tried couple times but it is showing incorrect. Please help me.. Thank you.
y=sin(x)/x
Your answer should be a linear function of x where the coefficients are accurate to at least two decimal places. You can enter π in your answer as "pi" (without the quotes).
I am not able to figure out how to find the answer. I tried couple times but it is showing incorrect. Please help me.. Thank you.
Answers
Answered by
bobpursley
linearization.
f(x)=f(a)+f'(a)(x-a)
Well, f(a)=cos PI/3
f'(a)=-sin(PI/3)
f(x)=cosPI/3-sin(PI/3)*(x-PI/3)
find with your calculator cosPI/3, and sin PI/3 and you have your linear equation.
f(x)=f(a)+f'(a)(x-a)
Well, f(a)=cos PI/3
f'(a)=-sin(PI/3)
f(x)=cosPI/3-sin(PI/3)*(x-PI/3)
find with your calculator cosPI/3, and sin PI/3 and you have your linear equation.
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