Asked by Anonymous
find the linearization of y= square root (x+1) using the quadratic approximation?
Answers
Answered by
oobleck
you want a linear or a quadratic?
in either case, you need to specify a particular point where teh approximation is good near that point. At x=h,
linear: f(x) ≈ f(h) + f'(h)(x-h)
quadratic: f(x) ≈ f(h) + f'(h)(x-h) + 1/2 f"(h) (x-h)^2
so pick a point and plug and chug.
in either case, you need to specify a particular point where teh approximation is good near that point. At x=h,
linear: f(x) ≈ f(h) + f'(h)(x-h)
quadratic: f(x) ≈ f(h) + f'(h)(x-h) + 1/2 f"(h) (x-h)^2
so pick a point and plug and chug.
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.