Asked by Fred
Find the linearization of f(x)=cos(x)-sin(2x) at x = 0.
Answers
Answered by
Reiny
L(x) = f(a) + f ' (a) (x-a) , where x = a
f(x) = cosx - sin 2x
f ' (x) = -sinx - 2cos 2x
L(x) = f(0) + f ' (0) (x-0)
= 1-0 + (0-2)(x-0)
= 1 - 2x
f(x) = cosx - sin 2x
f ' (x) = -sinx - 2cos 2x
L(x) = f(0) + f ' (0) (x-0)
= 1-0 + (0-2)(x-0)
= 1 - 2x
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