Asked by Honey
A package is thrown downward with an initial velocity of -5 ft/sec from a helicopter at 300 ft. A) what is the height of the package in 2 sec? B) how long does it take to hit the ground?
Round answer to 2 decimals Enter: blank ft,blank sec.
Round answer to 2 decimals Enter: blank ft,blank sec.
Answers
Answered by
Reiny
the equation is
height = -16t^2 - 5t + 300
so when t=2
height = -16(4) - 5(2) + 300
= 226 ft
to hit the ground, height =0
0 = -16t^2 - 5t + 300
16t^2 + 5t - 300 = 0
t = (-5 ± √19225)/32
= 4.176.. or a negative, of course negative time would be inadmissable
it would take appr 4.18 seconds to hit the ground
height = -16t^2 - 5t + 300
so when t=2
height = -16(4) - 5(2) + 300
= 226 ft
to hit the ground, height =0
0 = -16t^2 - 5t + 300
16t^2 + 5t - 300 = 0
t = (-5 ± √19225)/32
= 4.176.. or a negative, of course negative time would be inadmissable
it would take appr 4.18 seconds to hit the ground
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