a baseball is thrown downward from a 12.5m tower with an initial speed of 4.5m/s. determine the speed at which it hits the ground and the time of travel.

Answer 1

V^2 = Vo^2 + 2g*h.
V^2 = (4.5)^2 + 19.6*12.5 = 265.25.
V = 16.29 m/s.

Tf = (V-Vo)/g = (16.29-4.5) / 9.8 = 1.20 s. = Fall time.

Answer 2

Lone

Answer 3

Lone