Asked by Jenna
A ball is thrown downward, with an initial speed of 8.09 m/s, from a height of 30.1 m. After what time interval does the ball strike the ground?
Answers
Answered by
bobpursley
h=Vo*t + 1/2 g t^2
g=-9.8 Vo= -8.09 h=-30.1
solve the quadratic for time t.
g=-9.8 Vo= -8.09 h=-30.1
solve the quadratic for time t.
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