It hits the ground when the height is back to zero.
just solve for t when h=0
use your normal methods to solve
16t^2 + 14t - 100 = 0
A ball is thrown downward from the top of a 100-foot building with an initial velocity of 14 feet per second. The height of the ball h after t seconds is given by the equation h=-16t^2-14t+100.
How long after the ball is thrown will it strike the ground?
2 answers
Garbage
2 answers