Asked by Rachel

A ball is thrown downward from the top of a 100-foot building with an initial velocity of 14 feet per second. The height of the ball h after t seconds is given by the equation h=-16t^2-14t+100.

How long after the ball is thrown will it strike the ground?
Answered by Steve
It hits the ground when the height is back to zero.

just solve for t when h=0
use your normal methods to solve

16t^2 + 14t - 100 = 0
Answered by Joj
Garbage
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