Question
A ball is thrown downward from the top of a 100-foot building with an initial velocity of 14 feet per second. The height of the ball h after t seconds is given by the equation h=-16t^2-14t+100.
How long after the ball is thrown will it strike the ground?
How long after the ball is thrown will it strike the ground?
Answers
It hits the ground when the height is back to zero.
just solve for t when h=0
use your normal methods to solve
16t^2 + 14t - 100 = 0
just solve for t when h=0
use your normal methods to solve
16t^2 + 14t - 100 = 0
Garbage
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