Asked by kai
a ball is thrown downward from the too of 110 ft bldg with an initial velocity of 14ft per second. the height of ball h after t seconds is given by the equation h = -16t^2-14t +110.
how long after ball is thrown will it hit the ground
how long after ball is thrown will it hit the ground
Answers
Answered by
Reiny
when it is at ground level , h = 0
16t^2 + 14t - 110=0
8t^2 + 7t - 55 = 0
t = (-7 ± √1809)/16 = 2.22 or a negative
so it took 2.22 seconds before it hit the ground
16t^2 + 14t - 110=0
8t^2 + 7t - 55 = 0
t = (-7 ± √1809)/16 = 2.22 or a negative
so it took 2.22 seconds before it hit the ground
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.