Question
If a stone is thrown downward with a speed of 15m/s from a cliff that is 80m high, its height in meters, after t seconds is h(t) = 80-15t-4.9t^2. Determine the stone's average rate of change of the distance between 0s and 1s
1. -34,6m/s
2. 20.9m/s
3. 19.9m/s
4. 34.6m/s
1. -34,6m/s
2. 20.9m/s
3. 19.9m/s
4. 34.6m/s
Answers
oobleck
since the interval is [0,1], the slope is
(f(1)-f(0))m/(1-0)s = (60.1 - 80)/1 = -19.9 m/s
(f(1)-f(0))m/(1-0)s = (60.1 - 80)/1 = -19.9 m/s