Asked by Michelle27

Give exact approximate solutions? HUH? to three decimal places.

y^2-20y+100=64

In terms of i and use radicals if needed.

:-) Thanks
Answered by visoth
bring the 64 over so you have

y^2 - 20y + 36

im not sure if you can factor this so just use quadratic formula

Answered by Damon
[ 20 +/- sqrt(400 -144) ]/2

= 10 +/- .5 sqrt 256

= 10 +/- 8

= 2 or 18