Asked by chelsea
give exact and approximate to three decimals places x^2+8x+16=25 Please help me solve this
Answers
Answered by
Henry
x^2+8x+16-25 = 0,
x^2+8x-9 = 0,
(x+9(x-1) = 0,
x+9 = 0,
X = -9.
x-1 = 0,
X = 1.
Solution set: X = -9, and X = 1.
x^2+8x-9 = 0,
(x+9(x-1) = 0,
x+9 = 0,
X = -9.
x-1 = 0,
X = 1.
Solution set: X = -9, and X = 1.
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