Asked by Gary
Give exact and approximate solutions to three decimal places for y.
y^2-6y+9=64
If anyone can help with this problem I would really appriciate it. Thanks
y^2-6y+9=64
If anyone can help with this problem I would really appriciate it. Thanks
Answers
Answered by
drwls
Rewrite it in standard form
y^2 -6y -55 = 0
and then factor:
(y+11)(y-5) = 0
The answers are exact integers, so you don't have to worry about decimal places, unless that want you to write 5 as 5.000, etc.
y^2 -6y -55 = 0
and then factor:
(y+11)(y-5) = 0
The answers are exact integers, so you don't have to worry about decimal places, unless that want you to write 5 as 5.000, etc.
Answered by
Gary
Thank you for your help. So just to make sure its 11, 5 right. 5 is positive not negative??
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