Question

if f varies jointly as q^2 and h, and if f = 72 when q = 3 and h = 4, find h when f = 48 and q = 2

Answer 1

f = khq^2 , where k is a constant

given: f = 72 , q=3 , h=4
72 = k(4)(9)
k = 2

so f = 2hq^2
when f=48 , and q=2
48 = 2h(4)
h = 6

Answer 2

is fbs jointly as q 2 and h and f = 24 when q = 2 and h = 2 find x when q = 3 and h = 4