6g of metal M react completely with 23.66g of chlorine to form 29.66g of the metallic chloride. Find the empirical formula of the metallic chloride. (M = 27, Cl = 35.5)

Answer 1

Convert grams to mols.
6/27 = ?
23.66/35.5 = ?
Now find the ratio of M to Cl. The easy way to do that (if the answer isn't obvious at this point) is to divide the smaller number by itself, then divide the other number by the same small number.

Answer 2

6/27=0.2 23.66/35.
5=0.6
0.2/0.2=1 0.6/0.2=3
M1CL3

Answer 3

6g/M27 23.66/35.5 = 0.6 0.2/0.2=1 0.6/0.2 = 3 EMPIRICAL FORMULAR = M1CL3 CHILEZ

Answer 4

Divide by their relative atomic mass
6/27=0.222
23.66/35.5=0.666
Divide by the smallest ratio
0.222/0.222 =1
0.666/0.222=3
MCl3

Answer 5

M=6/27 Cl=23.66/35.5
M=0.2 Cl=0.6
Divide by the smallest number
M=0.2/0.2 Cl=0.6/0.2
M=1 Cl=3
Empirical formula=MCl3

Answer 6

Element = M Cl
R.A.M = 23.66 6
Mole ratio = 23.66/35.5,

Answer 7

M C
23.66 6

divide R.A.M by the atomic number

23.66/35.5 6/27
=0.22 =0.66
divide both side by the smallest
0.22/0.22 0.66/0.22
=1 =3
Emperical formular = MCl3

Answer 8

is this correct

Answer 9

The empirical formula in element

Answer 10

Where did you find 6

Answer 11

Sorry I asked a stupid question,l have realized my mistake and found the 6

Answer 12

Please house how did u get dis 27

Answer 13

The metal m is 27

Answer 14

6/27=0.22222....
29.66g/35.5=0.66648
Ratio of M to cl is =1:6
Emperical formula is =Mcl3