Asked by Haley
                A batter hits a pop-up straight up over home plate at an initial velocity of 29 m/s. The ball is caught by the catcher at the same height that it was hit. At what velocity will the ball land in the catcher's mitt? 
none of these
29 m/s
14.5 m/s
-14.5 m/s
-29 m/s
            
            
        none of these
29 m/s
14.5 m/s
-14.5 m/s
-29 m/s
Answers
                    Answered by
            drwls
            
    -29. Total energy is conserved so the kinetic energy (and v^2) when caught must be the same as when the ball was hit. However, the direction of the velocity changes from up to down. 
    
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