Asked by Bill
a softball batter hits a fly ball that is caught 3.8 seconds later, 88m from home plate. The ball is caught at the same height from which it was thrown.
What was its initial velocity?
What is the maximum height above its launch point that it reached?
What was its initial velocity?
What is the maximum height above its launch point that it reached?
Answers
Answered by
Scott
the velocity is the vector sum of the horizontal and vertical components
horizontal ... 88 m / 3.8 s
vertical ... time up equals time down
... (3.8 s / 2) * 9.8 m/s^2
the max height is half the initial vertical component, multiplied by half the flight time
horizontal ... 88 m / 3.8 s
vertical ... time up equals time down
... (3.8 s / 2) * 9.8 m/s^2
the max height is half the initial vertical component, multiplied by half the flight time
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