divide into vertical and horizontal problems
Vertical problem:
initial vertical speed = Vi = 28 sin 61
calculate Vi = 24.5 m/s
Now
v = Vi - 9.81 t
h = Hi + Vi t - 4.9 t^2 where Hi is initial height of 0.90 meter
h = 0 at ground
so
4.9 t^2 - Vi t - 0.90= 0
4.9 t^2 - 24.5 t - 0.90 = 0
solve quadratic
https://www.mathsisfun.com/quadratic-equation-solver.html
t = 5.04 seconds to hit ground
Now horizontal problem
u = 28 cos 61
distance = (28 cos 61) * 5.04
fielder goes (105 - distance)meters in 5.04 seconds
A batter hits a fly ball which leaves the bat 0.90 m above the ground at an angle of 61 degrees with an initial speed of 28 m/s heading towards center field. Ignore air resistance. (a) How far from the home plate would the ball land if not caught? (b) The ball is caught by the centerfielder who, starting at a distance of 105m from the home plate, runs straight towards home plate at a constant speed and makes the catch at ground level. What was his speed?
2 answers
a
2 answers