Question
a batter hits a baseball into the air. If the horizontal component (X-component) of the velocity is measured to be 20.4 m/s, if at it's max height the ball was in the air for 2.5 s, at what angle was the ball hit off the bat?
Answers
bobpursley
find initial vertical veloicty...
vf=vi-9.8 t but vf=-vi in the vertical
so vi=9.8*2.5/2
theta=arctan (vi/20.4)
vf=vi-9.8 t but vf=-vi in the vertical
so vi=9.8*2.5/2
theta=arctan (vi/20.4)