Asked by Haley
                A ball thrown horizontally at 27 m/s travels a horizontal distance of 51 m before hitting the ground. From what height was the ball thrown?
            
            
        Answers
                    Answered by
            Henry
            
    Dx = Xo*Tf = 51 m.
27*Tf = 51.
Tf = 51 / 27 = 1.89 s. = Fall time.
h = Yo*Tf + 0.5g*Tf^2.
h = 0 + 4.9*(1.89)^3 = 17.50 m.
    
27*Tf = 51.
Tf = 51 / 27 = 1.89 s. = Fall time.
h = Yo*Tf + 0.5g*Tf^2.
h = 0 + 4.9*(1.89)^3 = 17.50 m.
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