Question
A ball is thrown horizontally from a building 50.0 m high with a speed of 18 m/s. (a) find the vertical and horizontal components of the ball's initial velocity, (b)time of flight, (c) distance from the foot of the building where the ball will strike the ground, and (d) velocity when the ball will strike the ground.
Answers
You threw it horizontally so the initial vertical velocity is zero and the horizontal component is 18
Divide into a vertical problem and a horizontal problem
Verttical (falling) problem
Vi = 0
Hi = 50
a = -g = -9.81 meters/ second^2
v = 0 - 9.81 t
h = 50 - 0 t - 4.9 t^2
at bottom h = 0
4.9 t^2 = 50
t = 3.2 second falling time to ground
v = -9.81* 3.2 = - 31.3 meters/ second at h = 0, ground
HORIZONTAL problem
the thing flies at 18 m/s for 3.2 seconds
x = 18 * 3.2 meters
Divide into a vertical problem and a horizontal problem
Verttical (falling) problem
Vi = 0
Hi = 50
a = -g = -9.81 meters/ second^2
v = 0 - 9.81 t
h = 50 - 0 t - 4.9 t^2
at bottom h = 0
4.9 t^2 = 50
t = 3.2 second falling time to ground
v = -9.81* 3.2 = - 31.3 meters/ second at h = 0, ground
HORIZONTAL problem
the thing flies at 18 m/s for 3.2 seconds
x = 18 * 3.2 meters
Adrian threw a ball vertically upward, it return to his hands after 15seconds.(A) what was the ball initial speed? (B)with what speed did it return to the adrian's hands? (C) How high did it go?.
Can anyone answer it in complete solution thank you in advance
Can anyone answer it in complete solution thank you in advance
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