Asked by Abigail
A ball is thrown horizontally from the top of a building 150 meters high. The ball strikes the ground 56 meters horizontally from the point of release. What is the speed of the ball just before it strikes the ground?
Answers
Answered by
Henry
V^2 = Vo^2 + 2g*h
V^2 = 0 + 19.6*150 = 2,940
V = 54.2 m/s.
V^2 = 0 + 19.6*150 = 2,940
V = 54.2 m/s.
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