Question

A basketball is thrown horizontally from a window that is 22 meters high. If the initial velocity of the ball 18 m/s, find how long the ball takes to reach the ground and how far the ball lands from the building?

Answer 1

The time it takes for the ball to reach the ground is equal to the time it takes for the ball to fall 22 meters. This can be calculated using the equation t = (2*d)/v, where t is the time, d is the distance, and v is the velocity. Plugging in the values, we get t = (2*22)/18 = 2.22 seconds.

The distance the ball lands from the building can be calculated using the equation d = v*t, where d is the distance, v is the velocity, and t is the time. Plugging in the values, we get d = 18*2.22 = 39.96 meters.