Asked by Pat
A ball is thrown horizontally from a platform so that the initial height of the ball is 6.0 m above the level ground below. The ball lands 24 m from its original horizontal location. Find how fast the ball was thrown.
Show work i just don't understand
Show work i just don't understand
Answers
Answered by
Henry
d = Vo*t + 0.5g*t^2 = 6 m.
0 + 4.9t^2 = 6,
t^2 = 1.22,
Tf = 1.11 s. = Fall time or time in flight.
Dx = Vo*Tf = 24 m,
Vo*1.11 = 24,
Vo = 21.7 m/s.
0 + 4.9t^2 = 6,
t^2 = 1.22,
Tf = 1.11 s. = Fall time or time in flight.
Dx = Vo*Tf = 24 m,
Vo*1.11 = 24,
Vo = 21.7 m/s.
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