Asked by Sarah
A ball is thrown horizontally at 18m/s from the roof of a building lands 28metre from the base of the building. Calculate the height of the building.
Answers
Answered by
bobpursley
time to fall:
hf=hi-4.9t^2
hf=0
t= sqrt(hi/4.9)
Horizontaldistance:
d=vh*t
28=18*sqrt(hi/4.9)
solvefor hi
hi=4.9*(28/18)^2
hf=hi-4.9t^2
hf=0
t= sqrt(hi/4.9)
Horizontaldistance:
d=vh*t
28=18*sqrt(hi/4.9)
solvefor hi
hi=4.9*(28/18)^2
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