Asked by Katie
prove(sinx/cosx+1)+(cosx-1/sinx)=0
Answers
Answered by
Steve
sin/(cos+1) + (cos-1)/sin
= [sin*sin + (cos-1)(cos+1)]/[sin(cos+1)]
= (sin^2 + cos^2 - 1)/[sin(cos+1)]
= (1-1)/[sin(cos+1)]
= 0
= [sin*sin + (cos-1)(cos+1)]/[sin(cos+1)]
= (sin^2 + cos^2 - 1)/[sin(cos+1)]
= (1-1)/[sin(cos+1)]
= 0
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