Asked by liger
prove:
sinx/sec2x+cosx/csc2x=sin3x
sinx/sec2x+cosx/csc2x=sin3x
Answers
Answered by
Reiny
LS = sinx(cos2x) + cosx(sin 2x)
RS = sin(3x) = sin(2x + x)
= (sin 2x)cosx + (cos 2x) sinx
= LS
I am using sin(A+B) = sinAcosB + cosAsinB
RS = sin(3x) = sin(2x + x)
= (sin 2x)cosx + (cos 2x) sinx
= LS
I am using sin(A+B) = sinAcosB + cosAsinB
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