Question

A hydraulic jack is used to move an 8896 Newton car. If the area of the output piston is 8 times that of the input piston, how much input force is required to lift the the car?

Is this where I do P=PA or F1(A2)/F2 = A1(f2)/F2
F1 = A1F2/A2

Please help set this up.

F2=8896
A1=8
F1=?
A1=?
Force = pressure times area
so for pressure p in the fluid
p A1 = F1 Input side
p A2 = F2 Output side
so
F1 /A1 = F2/A2
F1 = F2 (A1/A2)
F1 = 8896 (1/8)

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