Asked by DariaV
A hydraulic jack has an input piston that is 1.2 cm2 in area and an output piston that is 144 cm2 in area. How much input or effort force in newtons is needed to lift a car that weighs 25,000 newtons?
Answers
Answered by
Damon
mechanical advantage = 144/1.2
so
25,000 (1.2 / 144) = 208 N
so
25,000 (1.2 / 144) = 208 N
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