Asked by Adedoyin

a certain hydraulic jack in a gas station lifts a 900 kg car,a distance of 0.25 m when a force of 150 Newtons pushes a piston through a distance of 20 cm.What is the IMA,AMA and efficiency
Answered by Damon
well 900 kg * 9.81 = 8829 Newtons lifted

work out doing lift = 8829 N * .25 m = 2207 Joules output
work in pushing piston = 150 N * 0.20 m = no way, typo
Answered by bobpursley
AMA=force out/force in=900(9.8)/150= 58.6
IMA= workout/workin=900*9.8*.25/(150*.20 )=73.5

efficiency = ama/ima
Answered by bobpursley
This is indeed a great jack, worthy of lab study.
Answered by Damon
I got 73.5 as many Joules out as I put in ?
Answered by Damon
Yess, I want one.
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