Asked by jay
A hydraulic plunger has a 12 cm diameter and a force of 350 kN acts on it. What is the pressure exerted on the plunger?
Answers
Answered by
Damon
r = 0.06 meters
A = pi r^2
F = 350,000 Newtons
p = F/A = 350,000 /(pi *.06^2)
in Newtons per square meter which is Pascals
A = pi r^2
F = 350,000 Newtons
p = F/A = 350,000 /(pi *.06^2)
in Newtons per square meter which is Pascals
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