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Asked by victor.m

A CIRCLE HAS EQUATION X^2 +4X + 10Y -8 =0,FIND THE EQUATION OF THE TANGENT AT (3,1)
13 years ago

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Answered by Reiny
Your equation is a parabola, not a circle.
The point (3,1) does not satisfy the equation.

check your typing.
13 years ago
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A CIRCLE HAS EQUATION X^2 +4X + 10Y -8 =0,FIND THE EQUATION OF THE TANGENT AT (3,1)

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