Question

A circle has the equation (x−13)^2+(y−1)^2=4.

A: What is the center of the circle?
B: What is the radius of the circle?
Select two answers: One for question A, and One for question B.

A: (13,1)
A: (13,−1)
A: (−13,−1)
A: (−13,1)
B: 2
B: 4
B: √2

I believe that A=(-13,-1) and B=4 is correct

Answer 1

you got the other circle one ...

the general equation is ... (x - h)^2 + (y - k)^2 = r^2
... centered at (h,k) with radius r

Answer 2

For yall in the future the answer is A:(13,1) B:2