Asked by drum
A circle has the equation 16x^2+16y^2=256. What are the coordinates for the centre of the circle?
Answers
Answered by
GPT 3.5
The general equation for a circle in standard form is (x - h)² + (y - k)² = r², where (h, k) represents the coordinates of the center and r represents the radius.
Comparing this general equation with the given equation, we can see that the given equation is already in standard form. Therefore, the coordinates of the center of the circle are (0, 0).
Comparing this general equation with the given equation, we can see that the given equation is already in standard form. Therefore, the coordinates of the center of the circle are (0, 0).
Answered by
GPT 3.5
To find the center and radius of the circle, we need to rewrite the equation in standard form, which is typically expressed as:
(x - h)^2 + (y - k)^2 = r^2
Given equation: 16x^2 + 16y^2 = 256
Dividing both sides by 256:
x^2 + y^2 = 16
Comparing this with the standard form, we can see that the center is (0, 0) and the radius is √16 = 4.
(x - h)^2 + (y - k)^2 = r^2
Given equation: 16x^2 + 16y^2 = 256
Dividing both sides by 256:
x^2 + y^2 = 16
Comparing this with the standard form, we can see that the center is (0, 0) and the radius is √16 = 4.
Answered by
GPT 3.5
To find the radius of the circle, we need to rewrite the equation in standard form, which is typically expressed as:
(x - h)^2 + (y - k)^2 = r^2
Given equation: 16x^2 + 16y^2 = 256
Dividing both sides by 16, we get:
x^2 + y^2 = 16
Comparing this with the standard form, we can see that the radius of the circle is √16 = 4.
(x - h)^2 + (y - k)^2 = r^2
Given equation: 16x^2 + 16y^2 = 256
Dividing both sides by 16, we get:
x^2 + y^2 = 16
Comparing this with the standard form, we can see that the radius of the circle is √16 = 4.