The perimeter of a rectangle is to be no greater than 300 in., and the length must be 125 in. Find the maximum width of the rectangle.

you have 2 lengths of 125, so you use up 250. Now you have 50 left, the 2 other sides must be even in order to be a rectangle. So divide 50 by 2 and you get 25. Therefore the rectangles sides are 125,125, 25,2.

But maybe use algebra. I do not know what math carly is taking.

2 L + 2 W </= 300
250 + 2 W </= 300
2 W </= 50
W </= 25

56>[=2

To find the maximum width of the rectangle, we need to use the given information and apply it to the formula for the perimeter of a rectangle.

Let's start by understanding the formula for the perimeter of a rectangle:

Perimeter = 2*(Length + Width)

We are given that the length of the rectangle is 125 inches, so we can substitute this value into the formula:

Perimeter = 2*(125 + Width)

Now we know that the perimeter must be no greater than 300 inches, so we can set up an inequality:

2*(125 + Width) ≤ 300

To find the maximum width, we need to solve this inequality by isolating the width variable.

Let's solve the inequality step by step:

2*(125 + Width) ≤ 300

First, distribute the 2:

250 + 2*Width ≤ 300

Then, subtract 250 from both sides:

2*Width ≤ 300 - 250

2*Width ≤ 50

Next, divide both sides by 2:

Width ≤ 50/2

Now we find:

Width ≤ 25

Therefore, the maximum width of the rectangle is 25 inches.