Asked by spirit73

the perimeter of a rectangle is 224 incles. the length exceeds the width by 64 inces. find the length and the width.


the length is _____ inches

and

the width is _____ inches
Answered by MathMate
Let
L=length
W=width = L-64
Perimeter = 224 = 2(L+W) = 2(L+L-64)
Solve for L.
Answered by Elanea
A=1/2h(b1+b2)
solve for b
Answered by MathMate
"A=1/2h(b1+b2)
solve for b"
I do not see the variable b in the expression: b1 and b2 are different variables than b.
In any case, I suggest you start a new thread for a new question.
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