Asked by spirit73
the perimeter of a rectangle is 224 incles. the length exceeds the width by 64 inces. find the length and the width.
the length is _____ inches
and
the width is _____ inches
the length is _____ inches
and
the width is _____ inches
Answers
Answered by
MathMate
Let
L=length
W=width = L-64
Perimeter = 224 = 2(L+W) = 2(L+L-64)
Solve for L.
L=length
W=width = L-64
Perimeter = 224 = 2(L+W) = 2(L+L-64)
Solve for L.
Answered by
Elanea
A=1/2h(b1+b2)
solve for b
solve for b
Answered by
MathMate
"A=1/2h(b1+b2)
solve for b"
I do not see the variable b in the expression: b1 and b2 are different variables than b.
In any case, I suggest you start a new thread for a new question.
solve for b"
I do not see the variable b in the expression: b1 and b2 are different variables than b.
In any case, I suggest you start a new thread for a new question.
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