Asked by scooby9132002
the perimeter of a rectangle is 62 m. then length is 10 m more than twice the width. find the dimensions
what is the length?
what is the width?
what is the length?
what is the width?
Answers
Answered by
Ms. Sue
2L + 2W = P
L = 10 + 2W
2(10 + 2W) + 2W = 62
20 + 4W + 2W = 62
6W = 42
W = 7
L = 14 + 10
L = 24
Check my figures.
L = 10 + 2W
2(10 + 2W) + 2W = 62
20 + 4W + 2W = 62
6W = 42
W = 7
L = 14 + 10
L = 24
Check my figures.
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