Asked by Jacqueline
A hydraulic jack is designed so that when the handle is pushed down 1 m, the piston raising the load moves up 0.015 m.
IMA= 66.67
AMA= 26.67
Efficiency= 40%
At this efficiency, what is the force required to lift a 5000 N weight?
IMA= 66.67
AMA= 26.67
Efficiency= 40%
At this efficiency, what is the force required to lift a 5000 N weight?