Asked by Shea
what is the maximum speed with which a car can round a turn of radius of 80.0m on a flat road if the coefficient of friction between tires and the road is .700?
Answers
Answered by
bobpursley
It matters if the road is banked. If unbanked, then force friction=centripetalForce
mg*mu=1/2 m v^2 / r
solve for v.
mg*mu=1/2 m v^2 / r
solve for v.
Answered by
Shea
I don't have a mass.
Answered by
Kole
bobpursley's comment is on the right track, but the equation IS wrong. mg(a.k.a. normal force) x Coefficient of friction = (m x v^2)/r then the normal force breaks down into: m x a(a = 9.8 at sea level) the equation will then look as so: 9.8m x mu = (mv^2)/r the m's will cancel out getting rid of mass. solve from there
Answered by
Phil
Kole is right but how would you find velocity
Answered by
A
You solve for velocity
There are no AI answers yet. The ability to request AI answers is coming soon!
Submit Your Answer
We prioritize human answers over AI answers.
If you are human, and you can answer this question, please submit your answer.