Question
What is the maximum speed (in meters/second) with which a 1300 kg car can round a turn of radius 700 m on a flat road, if the coefficent of friction between tires and road is 0.530 ?
Answers
drwls
centripetal force = max friction
force
M V^2/R = 0.53 M g
M cancels out
Solve for V
V = sqrt(0.53 g R) = 60.3 m/s
force
M V^2/R = 0.53 M g
M cancels out
Solve for V
V = sqrt(0.53 g R) = 60.3 m/s