A Spring (k=790 N/m) has a length of 48 cm when zero net force is applied to it. What will its length be when 230 N of force is applied to stretch it?

Answer 1

Divide the force (230 N) but the spring constant k (790 N/m), and you will get the increase in length. You should get 0.3026 m, which is 30.26 cm.

Add that to the original length to get the new spring length with that force applied. m. Assume that the spring is being stretched. (It could also be compressed, in which case you would subtract the 30.36 m)

Answer 2

this one is messed up

Answer 3

230 divided by 790
= .29113924m
= .291m