Question

a spring of spring length 5times 10 tothe power of 4 N/m,is between a rigid beam and the output piston of a hydraulic lever.an mpty container with negligable lengthsits on th input piston.the input piston has an area of Ai and the output piston has area 22.0Ai,initially spring is at rest length.how many kg of sand must be slowly poured into the container to press thr spring by 7cm?

Answer 1

The length of the spring is not 5*10^4 N/m; that is its stiffness (spring constant), k. You need to be more careful stating the question. Please capitalize the first work in sentences and use spaces before new words.

The force needed to compress the spring X = 0.07 m will be
F = k*X = 0.07*5*10^4 = 3500 N

Take the hydraulic lever mechanical advantage of 22 into account when computing the required amount of sand. You will need a sand weight of only 3500/22 = 159.1 N to compress the spring the desired amount. Divide that by g for the mass of sand in kg.