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A spring has a spring constant of 42 N/m. How much work is required to stretch the spring 1.5 cm from its equilibrium position?
14 years ago

Answers

bobpursley
work= 1/2 k x^2 = 1/2 42N/m * (.0015m)^2
14 years ago
Jen
4.725
7 years ago

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