Question

A spring with a spring constant of 1.50 102 N/m is attached to a 1.2 kg mass and then set in motion.
(a) What is the period of the mass-spring system?
s
(b) What is the frequency of the vibration?
Hz

Answer 1

look at the units:
spring constant= N/m=(kg*m/s)/m = kg/s

to get seconds (period): I want s in the numerator. kg / (kg/s) = s

to get frequency (s^-1): I want s in the denominator: 1/period

Answer 2

opps!
spring constant= N/m=(kg*m/s^2)/m = kg/s^2
econds (period): I want s in the numerator. kg / (kg/s) = s^2 (square root it?)

Answer 3

period = T = 2Pi √(m/k)
I looked it up. my derivation with units was correct except for the fact that it's multiplied by 2 pi

Answer 4

A SPRING MAKES 6O REVOLUTIONS IN 15 SECOND,FIND THE PERIOD AND THE FREQUENCY OF THE VIBRATION,