Question
a spring with a spring constant 30.0 N/m is stretched 0.200 m from its equilibrium position. How much work must be done to stretch it an additional 0.100 m?
Answers
drwls
It equals the potential energy change.
(1/2)k [(0.3)^2 - (0.2)^2] (Joules)
(1/2)k [(0.3)^2 - (0.2)^2] (Joules)