Asked by grey
A horizontal spring with spring constant of 120 N/m is compressed a distance of 0.25 m and placed in front of a ramp angled at 30° above the horizontal. A 1.5 kg ball is placed in front of it and released. How far will the ball roll up the 30° ramp? Again assume there is no friction.
Answers
Answered by
Damon
hey, just like the last one !
PE = (1/2) k x^2
PE = m g h = m g d sin 30 = .5 m g d
if d is distance along the ramp
PE = (1/2) k x^2
PE = m g h = m g d sin 30 = .5 m g d
if d is distance along the ramp
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