A horizontal spring with spring constant of 120 N/m is compressed a distance of 0.25 m and placed in front of a ramp angled at 30° above the horizontal. A 1.5 kg ball is placed in front of it and released. How far will the ball roll up the 30° ramp? Again assume there is no friction.

1 answer

hey, just like the last one !

PE = (1/2) k x^2

PE = m g h = m g d sin 30 = .5 m g d
if d is distance along the ramp