Question
4cos^2 theta = 3 where 0 degrees < theta< 360
Answers
Jai
4cos^2 theta = 3
cos^2 theta = 3/4
cos (theta) = sqrt(3) / 2
theta = arccos [ sqrt(3) / 2 ]
theta = π/6 , 11π/6
hope this helps~ XD
cos^2 theta = 3/4
cos (theta) = sqrt(3) / 2
theta = arccos [ sqrt(3) / 2 ]
theta = π/6 , 11π/6
hope this helps~ XD
Jai
oops i forgot the +/- sign:
cos (theta) = +/- sqrt(3) / 2
theta = +/- arccos [ sqrt(3) / 2 ]
theta = π/6 , 11π/6 , 5π/6 , 7π/6
cos (theta) = +/- sqrt(3) / 2
theta = +/- arccos [ sqrt(3) / 2 ]
theta = π/6 , 11π/6 , 5π/6 , 7π/6